2053/3348

2053/3348

2000 ban oi

9 465 500 nha bạn

131 . 27 - 31 . 27 - 7.100

5, 31+1240++1829=3100

6. -19+836+1829=2646

7.  54.43-32.35=2322-1120=1202

8 2018(31+16+50)=2018.97=195746

9. 16(34-21+55)=16.68=1088

10. 63(29-31-98)=63.(-100)=-6300

cả lời giải thì

mới được

bạn ạ

Phép tính trên bằng 30380 nha bạn!

Bài 2:

\(A=\dfrac{3}{2\cdot5}+\dfrac{3}{5\cdot8}+...+\dfrac{3}{17\cdot20}\)

\(=\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+...+\dfrac{1}{17}-\dfrac{1}{20}\)

\(=\dfrac{1}{2}-\dfrac{1}{20}=\dfrac{9}{20}\)

\(B=\dfrac{5^2}{1\cdot6}+\dfrac{5^2}{6\cdot11}+...+\dfrac{5^2}{26\cdot31}\)

\(=5\left(\dfrac{5}{1\cdot6}+\dfrac{5}{6\cdot11}+...+\dfrac{5}{26\cdot31}\right)\)

\(=5\left(1-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{11}+...+\dfrac{1}{26}-\dfrac{1}{31}\right)\)

\(=5\left(1-\dfrac{1}{31}\right)=5\cdot\dfrac{30}{31}=\dfrac{150}{31}\)

Bài này mình làm rồi bạn NGUYỆT ạ

\(B=3+3^2+3^3+3^4+...+3^{2009}+3^{2010}\)

\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{2009}+3^{2010}\right)\)

\(=3\left(1+3\right)+3^3\left(1+3\right)+...+3^{2009}\left(1+3\right)\)

\(=4.\left(3+3^3+...+3^{2009}\right)\)

⇒ \(B\) ⋮ 4

b: \(C=5\left(1+5+5^2\right)+...+5^{2008}\left(1+5+5^2\right)=31\cdot\left(5+...+5^{2008}\right)⋮31\)

x+(-45)=(-62)+17

x+(-45)=-45

x        =-45+45

x        =0

 (689-31)-(269-111)

=689-31-269+111

=(689+111)-(31+269)

=  800       -    300

=           500

1) x + ( -45 ) = -45

x = -45 - ( -45)

x= 0

300

300

= 300